A) 1 unit
B) 2 units
C) 3 units
D) 4 units
Correct Answer: B
Solution :
Let at any time t, the length of a side of the square be \[x\]. Then, \[A=Area={{x}^{2}}\] and \[\text{P = Perimeter = }4x\] \[\Rightarrow \] \[\frac{dA}{dt}=2x\frac{dx}{dt}\]and \[\frac{dP}{dt}=4\frac{dx}{dt}\] It is given that \[\frac{dA}{dt}=\frac{dP}{dt}\] \[\Rightarrow \] \[2x\frac{dx}{dt}=4\frac{dx}{dt}\Rightarrow x=2\]You need to login to perform this action.
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