A) HP
B) AP
C) GP
D) None of these
Correct Answer: B
Solution :
It is given that \[{{r}_{1}},{{r}_{2}}\]and \[{{r}_{3}}\]are in HP. \[\Rightarrow \] \[\frac{2}{{{r}_{2}}}=\frac{1}{{{r}_{1}}}+\frac{1}{{{r}_{3}}}\] \[\Rightarrow \] \[\frac{2(s-b)}{\Delta }=\frac{s-a}{\Delta }+\frac{s-c}{\Delta }\] \[\Rightarrow \] \[2a-2b=2s-a-c\] \[\Rightarrow \] \[2b=a+c\] Hence, a, b and c are in APYou need to login to perform this action.
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