A) (i)
B) (ii)
C) (iii)
D) Both (ii) and (iii)
Correct Answer: B
Solution :
The inductor (L) will not work on DC so as the switch 5 is closed current through L is zero and it acts as open circuit. \[{{i}_{1}}=0\] SO, \[{{i}_{2}}>{{i}_{3}}>{{i}_{1}}\] \[i_{3}^{0}=\frac{E}{2R}\]You need to login to perform this action.
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