A) Zero
B) 25 dyne
C) 30 dyne
D) 150 dyne
Correct Answer: B
Solution :
The given condition can be shown as Net force on B, \[{{F}_{net}}=\sqrt{F_{A}^{2}+F_{C}^{2}}\] \[\therefore \] \[{{F}_{A}}=\frac{5\times 12}{{{(3)}^{2}}}=15\] dyne and \[{{F}_{C}}=\frac{12\times 20}{{{(4)}^{2}}}=15\] dyne So, \[{{F}_{net}}=\sqrt{{{(20)}^{2}}+{{(15)}^{2}}}=25\] dyne.You need to login to perform this action.
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