A) 1.20-
B) 2.45
C) 3.55
D) 5.95
Correct Answer: C
Solution :
When an extra electron is added in nitrogen atom, added electron will be screened by five electrons in second orbit \[(2{{s}^{2}}2{{p}^{3}})\] and two electrons in first orbit \[(1{{s}^{2}})\]. Now screening constant, \[\sigma =5\times 0.35\] in nth orbit \[+2\times 0.85\] in \[(n-1)th\] orbit = 1.75 + 1.70 = 3.45 \[\therefore \] Effective nuclear charge = 7 - 3.45 = 3.55You need to login to perform this action.
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