A) \[\frac{6}{5}\]
B) \[\frac{5}{6}\]
C) 1
D) \[\frac{4}{5}\]
Correct Answer: A
Solution :
\[y=k{{t}^{2}}\] \[\frac{{{d}^{2}}y}{d{{t}^{2}}}=2k\] or \[a=2m/{{s}^{2}}\] (as\[k=1m/{{s}^{2}}\]) \[{{T}_{1}}=2\pi \sqrt{\frac{l}{g}}\] and \[{{T}_{2}}=2\pi \sqrt{\frac{l}{g+{{a}_{y}}}}\] \[\therefore \] \[\frac{T_{1}^{2}}{T_{2}^{2}}=\frac{g+{{a}_{y}}}{g}\] \[=\frac{10+2}{10}=\frac{6}{5}\]You need to login to perform this action.
You will be redirected in
3 sec