A) \[\frac{1}{\cos x}\]
B) \[\frac{1}{\sin x}\]
C) \[\frac{1}{\tan x}\]
D) \[\cos x\]
Correct Answer: A
Solution :
In magnetic meridian, angle of dip is given by \[\tan \theta =\frac{V}{H}\] ...(i) When dip circle is rotated in vertical plane, then \[\tan \theta '=\frac{V}{H\cos x}\] \[\therefore \] \[\frac{\tan \theta '}{\tan \theta }=\frac{1}{\cos x}\]You need to login to perform this action.
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