A) zero
B) \[10\text{ }m/{{s}^{2}}\]
C) \[4\text{ }m/{{s}^{2}}\]
D) \[12\text{ }m/{{s}^{2}}\]
Correct Answer: C
Solution :
Force on the block of 10 kg \[=ma=10\times 12=120N\] The total force applied = 200 N The force acting on block of 20 kg \[=200-120=80\text{ }N\] The acceleration of block of 20 kg \[=\frac{80}{20}=4\,m/{{s}^{2}}\]You need to login to perform this action.
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