A) +540.3
B) +727.3
C) \[-166.9\]
D) +19.8
Correct Answer: D
Solution :
Key Idea: \[\Delta S={{S}_{p}}-{{S}_{R}}\] \[{{H}_{2}}(g)+C{{l}_{2}}(g)\xrightarrow[{}]{{}}2HCl(g)\] Given \[{{S}^{o}}H(g)=130.6J{{K}^{-1}}/mol\] \[{{S}^{o}}C{{l}_{2}}(g)=223.0\text{ }J{{K}^{-1}}/mol\] \[{{S}^{o}}HCl(g)=186.7\text{ }J{{K}^{-1}}/mol\] \[\Delta S=2{{S}^{o}}HCl-({{S}^{o}}{{H}_{2}}+{{S}^{o}}C{{l}_{2}})\] \[=2\times 186.7-(130.6+223.0)\] \[=373.4-353.6=19.8\text{ }J{{K}^{-1}}mo{{l}^{-1}}\]You need to login to perform this action.
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