A) 0.4 L
B) 0.8 L
C) 27.8 L
D) 55.6 L
Correct Answer: A
Solution :
Key Idea: Problem is solved on the basis of Charle?s law\[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\] Given\[{{V}_{1}}=0.2L,{{V}_{2}}=?,{{T}_{1}}=273\,K,{{T}_{2}}=467\,K\] \[\therefore \] \[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\] Or \[\frac{0.2}{273}=\frac{{{V}_{2}}}{476}\] \[\therefore \] \[{{V}_{2}}=\frac{476\times 0.2}{273}=0.4\,L\]You need to login to perform this action.
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