A) 3.6kg
B) 3.3kg
C) 1kg
D) \[1\,mg\]
Correct Answer: A
Solution :
Mass of copper liberated \[m=zit\] \[=z\left( \frac{P}{V} \right)t\] \[=(3.3\times {{10}^{-7}})\left( \frac{100\times 36\times {{10}^{5}}}{33} \right)\] \[=3.6\,kg\]You need to login to perform this action.
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