A) \[1.96\times {{10}^{8}}m/s\]
B) \[2.12\times {{10}^{8}}m/s\]
C) \[3.18\times {{10}^{8}}m/s\]
D) \[3.33\times {{10}^{8}}m/s\]
Correct Answer: B
Solution :
\[\frac{{{c}_{1}}}{{{c}_{2}}}=\frac{\sin i}{\sin r}\] \[\therefore \] \[\frac{3\times {{10}^{8}}}{{{c}_{2}}}=\frac{\sin {{45}^{o}}}{\sin {{30}^{o}}}=\frac{0.707}{0.5}\] So, \[{{c}_{2}}=\frac{3\times {{10}^{8}}\times 0.5}{0.707}\] \[=2.12\times {{10}^{8}}m/s\]You need to login to perform this action.
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