A) \[1.2\mu F\]
B) \[3.6\mu F\]
C) \[2\mu F\]
D) \[1.4\mu F\]
Correct Answer: D
Solution :
Equivalent capacitance of \[2.5\mu F\] and \[1\mu F\]which are conceded in parallel is \[{{C}_{P}}=2.5+1=3.5\] Now \[{{C}_{P}}\] and C are connected in series so equivalent capacitance, \[{{C}_{PQ}}=\frac{C\times 3.5}{C+3.5}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,1=\frac{C\times 3.5}{C+3.5}\] or \[C+3.5=3.5C\] or \[2.5C=3.5\] or \[C=1.4\mu F\]You need to login to perform this action.
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