A) 4 \[\Omega \]
B) 3 \[\Omega \]
C) 2.5\[\Omega \]
D) 2\[\Omega \]
Correct Answer: D
Solution :
Equivalent resistance of series connection along PS and SR \[{{R}_{S}}=3+3=6\Omega \] and equivalent circuit equivalent resistance of parallel combination is \[{{R}_{PQ}}=\frac{6\times 6}{6+6}=3\Omega \] and equivalent resistance is Now, equivalent resistance of PQ and QR is \[R=3+3=6\] and finally the resistance between P and R \[{{P}_{PR}}=\frac{6\times 3}{6+3}=\frac{18}{9}=2\Omega \]You need to login to perform this action.
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