A) 1
B) 2
C) \[\frac{1}{2}\left( \frac{i-{{i}_{a}}}{2i-{{i}_{a}}} \right)\]
D) \[\left( \frac{2i-{{i}_{a}}}{i-{{i}_{a}}} \right)\]
Correct Answer: D
Solution :
Let resistance of galvanometer = G Current in galvanometer \[={{i}_{a}}\] Shunt resistance \[{{S}_{1}}=\frac{{{i}_{a}}G}{i-{{i}_{a}}}\] ??(i) \[{{S}_{2}}=\frac{{{i}_{a}}G}{2i-{{i}_{a}}}\] ??.(ii) From eq. (1) and (2) \[\frac{{{S}_{1}}}{{{S}_{2}}}=\frac{2i-{{i}_{a}}}{i-{{i}_{a}}}\]You need to login to perform this action.
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