A) \[60{}^\circ \]
B) \[90{}^\circ \]
C) \[45{}^\circ \]
D) \[30{}^\circ \]
Correct Answer: A
Solution :
Deflection produced in needle \[\tan \theta =\frac{{{B}_{2}}}{{{B}_{1}}}\] \[=\frac{\sqrt{3}}{1}=\sqrt{3}=\tan {{60}^{o}}\] \[\theta ={{60}^{o}}\]You need to login to perform this action.
You will be redirected in
3 sec