A) \[2.86MeV\]
B) \[6.79MeV\]
C) \[4.46MeV\]
D) \[8.24MeV\]
Correct Answer: B
Solution :
Mass of \[\alpha -\]-particle \[{{(}_{2}}H{{e}^{4}})=\] = mass of 2 protons + mass of 2 neutrons \[=2\times 1.0073+2\times 1.0087\] \[=4.032amu\] Mass decay \[=4.032-4.0028\] \[=0.02992amu\] Binding energy = mass defect \[\times \text{ }931MeV\] \[=0.0292\times 931\] \[=27.1852MeV\] Binding energy per nucleon \[=\frac{27.1852}{4}=6.7963MeV\]You need to login to perform this action.
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