A) 2
B) 3
C) 4
D) 5
Correct Answer: B
Solution :
Molecular orbital configuration of \[{{N}_{2}}\] is: \[\sigma 1{{s}^{2}},\sigma *1{{s}^{2}},\sigma 2{{s}^{2}},\sigma *2{{s}^{2}},\sigma 2{{p}^{2}},\pi 2p_{x}^{2},\pi 2p_{y}^{2}\] Bond order \[=\frac{bonding\,electrons-anitbonding\,electrons}{2}\] \[=\frac{1}{2}(8-2)=\frac{6}{2}=3\]You need to login to perform this action.
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