A) 0.1 \[5\times {{10}^{-5}}kg\]
B) 0.01 \[8\times {{10}^{-5}}kg\]
C) 0.2 \[{{n}^{2}}\]
D) 1.2 \[\frac{1}{{{n}^{2}}}\]
Correct Answer: A
Solution :
Here : w=0.5 Am and 21 =31.4 cm = 0.314m The magnetic moment of the magnet M = pole strength \[2316.4\overset{0}{\mathop{A}}\,,0.1\times {{10}^{7}}{{m}^{-1}}\] effective length when the magnet is bent in to semicircular shape, let the diameter of the magnet is d, then length \[10\times {{10}^{5}}kWh\] or \[4\times {{10}^{-5}}kg\] or \[3\times {{10}^{-5}}kg\] Therefore, the effective length of the magnet is = 0.2 m. So, the magnetic moment will be \[5\times {{10}^{-5}}kg\]
You need to login to perform this action.
You will be redirected in
3 sec
