A) \[Zn{{(OH)}_{2}}\]
B) \[ZnOH\]
C) \[N{{a}_{2}}Zn{{O}_{2}}\]
D) None of these
Correct Answer: C
Solution :
On treating zinc with excess of \[NaOH\], sodium zincate is obtained as major product. \[Zn+NaOH\xrightarrow{{}}N{{a}_{2}}Zn{{O}_{2}}+{{H}_{2}}\]
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