A) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}Br\]
B) \[C{{H}_{3}}Br\]
C) \[C{{H}_{2}}=CHC{{H}_{2}}Br\]
D) \[{{(C{{H}_{3}})}_{3}}CBr\]
Correct Answer: B
Solution :
\[{{S}_{N}}2\] mechanism involves the back side attack and formation of a transition state, thus less hindered alkyl halide readily undergoes \[{{S}_{N}}2\] mechanism. Among the given, \[C{{H}_{3}}Br\] (methyl bromide) is less hindered, thus hydrolysed by \[{{S}_{N}}2\] mechanism.
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