A) \[\mu \]
B) \[\frac{15\lambda }{(\mu -1)}\]
C) \[15(\mu -1)\lambda \]
D) \[25(\mu -1)\lambda \]
Correct Answer: B
Solution :
Intensity at a point having phase difference of \[\phi \] is At the central maxima \[{{I}_{0}}=4I\] At a distance y from the central fringe path difference \[\Delta x=d\times \frac{y}{D}\] Phase difference \[\phi =\frac{2\pi }{\lambda }(\Delta x)\] \[=\frac{2\pi }{\lambda }\left[ d\times \frac{y}{D} \right]=\frac{2\pi y}{\frac{D}{d}\lambda }=\frac{2\pi y}{\beta }\] \[\therefore \] The intensity at this point P \[I=4I{{\cos }^{2}}\left( \frac{\pi y}{\beta } \right)\] \[={{I}_{0}}{{\cos }^{2}}\left( \pi \frac{y}{\beta } \right)\]You need to login to perform this action.
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