A) \[{{v}_{P}}={{v}_{Q}}=0\]
B) \[{{v}_{P}}=0,{{v}_{Q}}=2v\]
C) \[\eta \]
D) \[\lambda \]
Correct Answer: A
Solution :
(a.)When outer sphere B is earthed only \[{{C}_{net}}={{C}_{1}}=\frac{4\pi {{\varepsilon }_{0}}ab}{b-a}\] When inner sphere is earthed, there will be two capacitors \[{{C}_{2}}={{C}_{1}}+{{C}_{1}}=\frac{4\pi {{\varepsilon }_{0}}ab}{b-a}+4\pi {{\varepsilon }_{0}}b\] \[=\frac{4\pi {{\varepsilon }_{0}}{{b}^{2}}}{b-a}\] \[\Rightarrow \] \[\frac{{{C}_{1}}}{{{C}_{2}}}=\frac{ab}{{{b}^{2}}}=\frac{a}{b}\]You need to login to perform this action.
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