A) \[{{x}^{2}}+{{y}^{2}}-2x+24=0\]
B) \[{{x}^{2}}+{{y}^{2}}-x-25=0\]
C) \[{{x}^{2}}+{{y}^{2}}-2x-24=0\]
D) \[{{x}^{2}}+{{y}^{2}}+2x+24=0\]
E) \[{{x}^{2}}+{{y}^{2}}-2y+24=0\]
Correct Answer: C
Solution :
Let r be the radius of a circle \[\because \] Circumference \[=10\pi \] \[\therefore \] \[2\pi r=10\pi \Rightarrow \]\[r=5\]unit \[\therefore \]Equation of circle with centre at (1, 0) and radius 5 is, \[{{(x-1)}^{2}}+{{(y-0)}^{2}}=25\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}-2x-24=0\]
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