CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    The value of\[\cos 1{}^\circ .\cos 2{}^\circ .\cos 3{}^\circ .....\cos 179{}^\circ \]is equal to:

    A)  \[\frac{1}{\sqrt{2}}\]                                    

    B)  \[0\]

    C)  \[1\]                    

    D)         \[-1\]

    E)  \[-\frac{1}{\sqrt{2}}\]

    Correct Answer: B

    Solution :

    \[cos\text{ }1{}^\circ -cos\text{ }2{}^\circ -\text{ }cos\text{ }3{}^\circ ...\text{ }cos\text{ }179{}^\circ \] \[=cos\text{ }1{}^\circ -cos\text{ }2{}^\circ -cos\text{ }3{}^\circ ...\text{ }cos\text{ }90{}^\circ ...\text{ }cos\text{ }179{}^\circ \]\[=0\]                                        (\[\because cos\text{ }90{}^\circ =0\])


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