A) 100 J
B) 300 J
C) 50 J
D) 20 J
E) 125J
Correct Answer: E
Solution :
Resultant force, \[F=\sqrt{{{(4)}^{2}}+{{(3)}^{2}}}=5\,N\] Acceleration, \[a=\frac{F}{m}=\frac{5}{10}=0.5\,m{{s}^{-2}}\] Velocity, \[v=0+at=0.5\times 10=5\text{ m/}s\] \[\therefore \] \[KE=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times 10\times {{(5)}^{2}}=125\,J\]You need to login to perform this action.
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