A) 120
B) 200
C) 100
D) 50
E) 30
Correct Answer: A
Solution :
\[I=k\tan \theta ,\]k being reduction factor and \[I\propto \frac{1}{R}\] \[\Rightarrow \] \[\frac{R+r}{(R+r)+R}=\frac{tan\theta }{\tan \theta }\] \[\Rightarrow \] \[\frac{4+2}{6+R}=\frac{\tan 30{}^\circ }{\tan 60{}^\circ }\] \[\Rightarrow \] \[R=12\,\Omega \]You need to login to perform this action.
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