A) 25 kW
B) 10 kW
C) 5 kW
D) 2.5 kW
E) 0.5 kW
Correct Answer: A
Solution :
\[{{F}_{net}}=30000\times 10\times \frac{1}{100}=3\times {{10}^{3}}N\] \[\therefore \] \[P=F.v=3\times {{10}^{3}}\times 30\times \frac{5}{18}=25\,kW\]You need to login to perform this action.
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