A) 0.01
B) 0.03
C) 0.02
D) 3
E) 2
Correct Answer: B
Solution :
\[{{I}_{cm}}=\frac{1}{2}M{{R}^{2}}=\frac{1}{2}\times 2\times {{(0.1)}^{2}}=0.01\,kg-{{m}^{2}}\] About an axis passing through the edge \[I={{I}_{cm}}+M{{R}^{2}}\] (Theorem of \[|\,\,|\]axis) \[=0.01+2\times {{(0.1)}^{2}}\] \[=0.03\,kg-{{m}^{2}}\]You need to login to perform this action.
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