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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    The equation of a simple harmonic motion is \[X=0.34\cos (3000t+0.74),\]where X and t are in mm and sec respectively. The frequency of the motion in Hz is:

    A)  \[3000\]                             

    B)  \[\frac{3000}{2\pi }\]    

    C)         \[\frac{0.74}{2\pi }\]     

    D)         \[\frac{3000}{\pi }\]

    E)  \[\frac{3000}{t}\]

    Correct Answer: B

    Solution :

                                 Here, \[\omega =3000\] \[\Rightarrow \] \[f=\frac{3000}{2\pi }Hz\]


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