A) \[\sqrt{\frac{1-k}{2}}\]
B) \[\sqrt{2-k}\]
C) \[\sqrt{\frac{2+k}{2}}\]
D) \[\sqrt{\frac{2-k}{2}}\]
E) \[\sqrt{\frac{k}{2}}\]
Correct Answer: E
Solution :
Given that, \[1+\cos x=k\] \[\Rightarrow \] \[2{{\sin }^{2}}(x/2)=k\] \[\Rightarrow \] \[\sin (x/2)=\sqrt{\frac{k}{2}}\]You need to login to perform this action.
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