CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    A cyclist is moving in a circular track of radius 80 m with a velocity v = 36 km/h. He has to lean from the vertical approximately through an angle: (Take \[g=10\text{ }m{{s}^{-2}})\]

    A)  \[{{\tan }^{-1}}(4)\]       

    B)         \[{{\tan }^{-1}}\left( \frac{1}{3} \right)\]

    C)  \[{{\tan }^{-1}}\left( \frac{1}{4} \right)\]              

    D)         \[{{\tan }^{-1}}(2)\]

    E)  \[{{\tan }^{-1}}\left( \frac{1}{8} \right)\]

    Correct Answer: E

    Solution :

    \[\tan \theta =\frac{{{v}^{2}}}{rg}\] \[\Rightarrow \]               \[\theta ={{\tan }^{-1}}\left( \frac{10\times 10}{80\times 10} \right)\]                                 \[\left( \because v=36\times \frac{5}{18}=10\,m/s \right)\]                 \[={{\tan }^{-1}}\left( \frac{1}{8} \right)\]


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