CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    Potassium permanganate acts as an oxidant in alkaline and acidic media. The final products formed from \[KMn{{O}_{4}}\] in the two conditions are respectively:

    A) \[Mn{{O}^{2-}}\]and \[M{{n}^{3+}}\]

    B) \[M{{n}^{3+}}\]and \[M{{n}^{2+}}\]

    C) \[M{{n}^{2+}}\]and \[M{{n}^{3+}}\]

    D) \[Mn{{O}_{2}}\]and \[M{{n}^{2+}}\]

    E) \[M{{n}^{2+}},Mn{{O}_{2}}\]

    Correct Answer: D

    Solution :

    In acidic medium: \[\overset{+7}{\mathop{KMn{{O}_{4}}}}\,\xrightarrow{{}}\overset{+2}{\mathop{MnS{{O}_{4}}}}\,\] In weak basic medium:                 \[KMn{{O}_{4}}\xrightarrow{{}}Mn{{O}_{2}}\]


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