A) 55 g
B) 11 g
C) 22 g
D) 33 g
E) 44 g
Correct Answer: A
Solution :
\[CaC{{O}_{3}}\xrightarrow[{}]{{}}C{{O}_{2}}\] \[(20+12+48=80)\,(12+32=44)\] \[80\text{ }g\text{ }CaC{{O}_{3}}\]produces \[=44\text{ }g\text{ }C{{O}_{2}}\] \[100\text{ }g\,CaC{{O}_{3}}\]produces\[=\frac{44}{80}\times 100\] \[=55g\]You need to login to perform this action.
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