A) \[{{E}_{1}}=6{{E}_{2}}\]
B) \[{{E}_{1}}=2{{E}_{2}}\]
C) \[{{E}_{1}}=4{{E}_{2}}\]
D) \[{{E}_{1}}=1/2{{E}_{2}}\]
E) \[{{E}_{1}}={{E}_{2}}\]
Correct Answer: B
Solution :
\[E=\frac{hc}{\lambda },\] h and c for both cases are same so, \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{16000}{8000}\] \[{{E}_{1}}=2{{E}_{2}}\]You need to login to perform this action.
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