A) 17
B) 83
C) 50
D) zero
E) 90
Correct Answer: A
Solution :
Percentage ionic character \[=\frac{experimental\text{ }value\text{ }of\text{ }DM}{theoretical\text{ }value\text{ }of\text{ }DM}\times 100\] \[=\frac{1.03}{6.12}\times 100\] \[=17%\]You need to login to perform this action.
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