A) copper electrode acts as a cathode then\[E{}^\circ \]cell is\[+0.46\text{ }V\]
B) silver electrode acts as anode then\[E{}^\circ \]cell is\[-0.34\text{ }V\]
C) copper electrode acts as anode then\[E{}^\circ \]cell is\[+0.46V\]
D) silver electrode acts as a cathode then\[E{}^\circ \]cell is\[-0.34\text{ }V\]
E) silver electrode acts as anode and\[E{}^\circ \]cell is \[+1.14V\]
Correct Answer: C
Solution :
\[E_{cell}^{o}=E_{cathode}^{o}-E_{anode}^{o}\] \[=E_{A{{g}^{+}}/Ag}^{o}-E_{C{{u}^{+}}/Cu}^{o}\] \[=-0.80-0.34\] \[=+0.46\]
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