A) 94.9 atm
B) 0.949 atm
C) 949 atm
D) 0.648 atm
E) 1.248 atm
Correct Answer: B
Solution :
\[{{P}_{{{H}_{2}}O}}={{X}_{{{H}_{2}}O}}{{P}_{total}}\] \[=0.0287\times 0.977\] \[=0.028\text{ }atm\] \[{{P}_{total}}={{P}_{dry\,air}}+{{P}_{{{H}_{2}}O}}\] \[{{P}_{dry\,air}}={{P}_{total}}-{{P}_{{{H}_{2}}O}}\] \[=0.977-0.028=0.949\text{ }atm\]You need to login to perform this action.
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