List I: Metal ions | List II: Magnetic moment (BM) | ||
1 | \[C{{r}^{3+}}\] | A | \[\sqrt{35}\] |
2 | \[F{{e}^{2+}}\] | B | \[\sqrt{30}\] |
3 | \[N{{i}^{2+}}\] | C | \[\sqrt{24}\] |
4 | \[M{{n}^{2+}}\] | D | \[\sqrt{15}\] |
E | \[\sqrt{8}\] |
A) 1-A, 2-C, 3-E, 4-D
B) 1-B, 2-C, 3-E, 4-A
C) 1-D, 2-C, 3-E, 4-A
D) 1-D, 2-E, 3-C, 4-A
E) 1-E, 2-A, 3-B, 4-C
Correct Answer: C
Solution :
\[\because \] \[\mu =\sqrt{n(n+2)}\] \[C{{r}^{3+}}(Z=24):3{{d}^{3}}4{{s}^{0}},\mu =\sqrt{3(3+2)}=\sqrt{15}\] \[F{{e}^{2+}}(Z=26):3{{d}^{6}}4{{s}^{0}},\mu =\sqrt{4(4+2)}=\sqrt{24}\] \[N{{i}^{2+}}(Z=28):3{{d}^{8}}4{{s}^{0}},\mu =\sqrt{2(2+2)}=\sqrt{8}\] \[M{{n}^{2+}}(Z=25):3{{d}^{5}}4{{s}^{0}},\mu =\sqrt{5(5+2)}=\sqrt{35}\]You need to login to perform this action.
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