question_answer

Consider the following compounds:

(i) chloroethene

(ii) benzene

(iii) 1, 3-butadiene

(iv) 1, 3, 5-hexatriene

All the carbon atoms are\[s{{p}^{2}}\]hybridized in:

A) (i), (iii), (iv) only

B) (i), (ii) only

C) (ii), (iii), (iv) only

D) (iii), (iv) only

E) (i), (ii), (iii) and (iv)

Correct Answer: E

Solution :

\[\underset{chloroethene}{\mathop{\underset{s{{p}^{2}}}{\mathop{ClCH}}\,=\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,,}}\,\]  all carbon atoms are \[s{{p}^{2}}\]hybridized \[\underset{1,\text{ }3-butadiene}{\mathop{\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{s{{p}^{2}}}{\mathop{CH_{2}^{}}}\,}}\,\] \[\underset{1,3,\text{ }5-hexatriene}{\mathop{\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,}}\,\]