A) \[IO_{3}^{-}\]and\[Xe{{O}_{3}}\]
B) \[PF_{6}^{-}\]and\[S{{F}_{6}}\]
C) \[BH_{4}^{-}\]and \[NH_{4}^{+}\]
D) \[CO_{3}^{2-}\]and\[NO_{2}^{-}\]
E) \[Si{{F}_{4}}\]and \[S{{F}_{4}}\]
Correct Answer: D
Solution :
\[IO_{3}^{-},Xe{{O}_{3}},\](\[s{{p}^{3}}\]hybridisation) pyramidal \[PF_{6}^{-},S{{F}_{6}}(s{{p}^{3}}{{d}^{2}})\]octahedral \[BH_{4}^{-},NH_{4}^{+},Si{{F}_{4}}(s{{p}^{3}})\]tetrahedral \[CO_{3}^{2-}(s{{p}^{2}})\]trigonal planar \[NO_{2}^{-}(s{{p}^{2}})\]bent (due to the lone pair) \[S{{F}_{4}}(s{{p}^{3}}d)\]square planar Hence,\[CO_{3}^{2-}\]and\[NO_{2}^{-}\]are not isostructural (same structure).
You need to login to perform this action.
You will be redirected in
3 sec
