A) 1.5%
B) 0.5%
C) 3%
D) 1%
E) 2%
Correct Answer: A
Solution :
From Keplers law, \[{{T}^{2}}\propto {{R}^{3}}\] Or\[{{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{2}}={{\left( \frac{{{R}_{2}}}{{{R}_{1}}} \right)}^{3}}={{\left( \frac{1.01R}{R} \right)}^{3}}={{(1+0.01)}^{3}}\] Or \[\frac{{{T}_{2}}}{{{T}_{1}}}={{(1+0.01)}^{3/2}}=1+\left( \frac{3}{2}\times 0.001 \right)\] Or \[\frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}}=\frac{1.5}{100}=1.5%\]
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