CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    An aromatic hydrocarbon with empirical formula\[{{C}_{5}}{{H}_{4}}\]on treatment with concentrated \[{{H}_{2}}S{{O}_{4}}\]gave a monosulphonic acid. 0.104 g of the acid required 10 mL of\[\frac{N}{20}NaOH\]for complete neutralization. The molecular formula of hydrocarbon is

    A)  \[{{C}_{5}}{{H}_{4}}\]                   

    B)  \[{{C}_{10}}{{H}_{8}}\]

    C)  \[{{C}_{15}}{{H}_{12}}\]              

    D)         \[{{C}_{20}}{{H}_{16}}\]

    E)  \[{{C}_{15}}{{H}_{20}}\]

    Correct Answer: C

    Solution :

    Empirical formula \[({{C}_{5}}{{H}_{4}})+{{H}_{2}}S{{O}_{4}}\to \]Monosulphonic acid 0.104 g of acid required 10 mL of \[\frac{N}{20}NaOH\] for completely neutralization \[\frac{0.104}{n(5\times 12+4\times 1)}=\frac{1}{20}\times 10\times {{10}^{-3}}\]                 \[n=\frac{104}{32}=3.25\approx 3\] The molecular formula of hydrocarbon will be C is\[{{C}_{15}}{{H}_{12}}\].


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