A) 45
B) 9
C) 18
D) 36
E) 27
Correct Answer: E
Solution :
Percentage of element M in\[{{M}_{2}}{{O}_{3}}=53\] Let the atomic mass of\[M=x\] Mass of\[M\]in \[{{M}_{2}}{{O}_{3}}=2x\] Total atomic mass of \[{{M}_{2}}{{\text{O}}_{3}}=2x+16\times 3\] \[=2x+48\] Percentage of an element \[=\frac{Mass\text{ }of\text{ }an\text{ }element\text{ }in\text{ }a\text{ }compound}{Total\text{ }mass\text{ }of\text{ }compound}\times 100\] \[53=\frac{2x}{2x+48}\times 100\] \[53(2x+48)=200x\] \[x=27\]
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