A) \[x-y+2=0\]
B) \[x+y-1=0\]
C) \[x+y-2=0\]
D) \[x-y+1=0\]
E) \[x+y+1=0\]
Correct Answer: D
Solution :
Given, \[\frac{{{x}^{2}}}{3}-\frac{{{y}^{2}}}{2}=1\] Here, \[{{a}^{2}}=3,\text{ }{{b}^{2}}=2\] \[\therefore \]Equation of tangent is \[y=mx\pm \sqrt{{{a}^{2}}{{m}^{2}}-{{b}^{2}}}\] \[\Rightarrow \] \[y=1.x\pm \sqrt{3-2}\] \[(\because m=1)\] \[\Rightarrow \] \[y=x\pm 1\] \[\Rightarrow \] \[x-y\pm 1=0\] Hence, option (d) Is correct;
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