A) \[\frac{16}{7}\]
B) \[\frac{25}{4}\]
C) \[\frac{25}{12}\]
D) \[\frac{16}{9}\]
E) \[\frac{23}{16}\]
Correct Answer: C
Solution :
Given, ellipse \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{7}=1\] \[\therefore \] \[{{e}_{1}}=\sqrt{1-\frac{7}{16}}=\frac{3}{4}\] and hyperbola \[\frac{{{x}^{2}}}{9}-\frac{{{y}^{2}}}{7}=1\] \[\therefore \] \[{{e}_{2}}=\sqrt{1+\frac{7}{9}}=\frac{4}{3}\] Now, \[{{e}_{1}}+{{e}_{2}}=\frac{3}{4}+\frac{4}{3}=\frac{25}{12}\]
You need to login to perform this action.
You will be redirected in
3 sec
