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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    The inductance of a coil in which a current of 0.1 A increasing at the rate of\[0.5\text{ }A{{s}^{-1}}\]represents a power flow of\[\frac{1}{2}W,\]is

    A)  2H                         

    B)         8H

    C)  20 H                     

    D)         10 H

    E)  5H

    Correct Answer: D

    Solution :

    \[U=\frac{1}{2}L{{I}^{2}}\] \[\therefore \]  \[\frac{du}{dt}=\frac{1}{2}L.2I\frac{dI}{dt}\] \[\therefore \]  \[D=LI\frac{dI}{dt}\] \[\therefore \]  \[L=\frac{P}{I\frac{dI}{dt}}=\frac{\left( \frac{1}{2} \right)}{0.1\times 0.5}=10\,H\]


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