A) 500
B) 100
C) \[\frac{500}{3}\]
D) \[\frac{250}{3}\]
E) \[10\sqrt{5}\]
Correct Answer: B
Solution :
\[{{E}_{0}}=\sqrt{\frac{{{\mu }_{0}}c{{P}_{av}}}{2\pi {{r}^{2}}}}=\sqrt{\frac{(4\pi \times {{10}^{-7}})\times (3\times {{10}^{8}})\times 1500}{2\pi \times {{(4)}^{2}}}}\] \[=100V{{m}^{-1}}\]
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