A) 0.01 M
B) 0.001 M
C) 0.1 M
D) 0.0001 M
E) 0.1010 M
Correct Answer: A
Solution :
\[[{{H}^{+}}]={{K}_{a}}.C\] Given, \[{{[{{H}^{+}}]}_{HCOOH}}={{[{{H}^{+}}]}_{C{{H}_{3}}COOH}}\] \[{{K}_{a}}.C=K_{a}^{}C\] \[\Rightarrow \] \[1.8\times {{10}^{-4}}\times 0.001=1.8\times {{10}^{-5}}\times C\] \[\therefore \] \[C=0.01\,M\]You need to login to perform this action.
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