CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    An 1% solution of\[KCl\](I),\[NaCl\](II),\[BaC{{l}_{2}}\](III) and urea (IV) have their osmotic pressure at thesame temperature in the ascending order (molar masses of\[NaCl,KCl,BaC{{l}_{2}}\]and urea are respectively 58.5, 74.5, 208.4 and 60 g. \[mo{{l}^{-1}})\].Assume 100% ionization of the electrolytes at this temperature

    A) \[I<III<II<\text{ }IV\]    

    B) \[III<I<II<IV\]

    C) \[I<\text{ }II<III<IV\]

    D)        \[I<\text{ }III<IV<II\]

    E) \[III<IV<I<II\]

    Correct Answer: E

    Solution :

    1% solution means 1 g solute is present in 100 mL of water. Osmotic pressure, \[\pi =\frac{iw\times RT}{M\times V}\] \[\therefore \]                  \[{{\pi }_{KCl}}=\frac{2\times 1\times 1000\times RT}{74.5\times 100}\]                                 \[=2\times 0.134\,RT\]                                 \[{{\pi }_{NaCl}}=\frac{2\times 1\times 1000\times RT}{58.5\times 100}\]                                 \[=2\times 0.171\,RT\]                                 \[{{\pi }_{BaC{{l}_{2}}}}=\frac{3\times 1\times 1000\times RT}{208.4\times 100}\]                                 \[=3\times 0.048\,RT\]                                 \[{{\pi }_{urea}}=\frac{1\times 1\times 1000\times RT}{60\times 100}\]                                 \[=1\times 0.167\,RT\] Since, temperature is same in all cases, the ascending order of osmotic pressure is \[III<IV<I<II\]


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